At first glance, this looks simple.<\/p>\n\n\n\n
Two identical glasses filled with the same liquid.
Points A and B are placed at the same depth.<\/p>\n\n\n\n
But\u2026 in the second glass, there\u2019s a floating object.<\/p>\n\n\n\n
And that\u2019s where the trick begins.<\/p>\n\n\n\n
Most people instantly think:
\ud83d\udc49 \u201cThe pressures must be different\u2026 there\u2019s an object in one of them!\u201d<\/p>\n\n\n\n
Sounds logical, right?<\/p>\n\n\n\n
But take a moment and think deeper.<\/p>\n\n\n\n
Pressure in a liquid doesn\u2019t depend on what\u2019s floating above. The floating object only displaces some water \u2014 it doesn\u2019t directly press down on point B in a way that changes the pressure at that depth.<\/p>\n\n\n\n So even though the setups look different\u2026 the physics behind them tells a different story.<\/p>\n\n\n\n \ud83d\udcac What was your answer? Be honest!<\/strong><\/p>\n\n\n\n \u2705 Final Answer:<\/strong>
It depends on depth, density of the liquid, and gravity<\/strong>.<\/p>\n\n\n\n
The pressure at A and B is the SAME.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"